What is the density of standard air if the specific volume is 13.33 cubic feet per pound?

What is the density of standard air if the specific volume is 13.33 cubic feet per pound?

• A. 0.070 pounds per cubic feet
• B. 0.075 pounds per cubic feet
• C. 0.080 pounds per cubic feet
• D. 0.085 pounds per cubic feet

Answer: (B)

To find the density of standard air when given the specific volume, we can use the relationship between density and specific volume. The specific volume is defined as the volume occupied by a unit mass of a substance, and it is the inverse of density. In mathematical terms, density is equal to the mass divided by volume, and the specific volume is volume divided by mass. Given the specific volume of 13.33 cubic feet per pound, we can calculate the density (in pounds per cubic foot) using the following formula: \[ \text{Density} = \frac{1}{\text{Specific Volume}} \] Substituting the specific volume into the equation gives: \[ \text{Density} = \frac{1}{13.33 \, \text{cubic feet per pound}} \approx 0.075 \, \text{pounds per cubic foot} \] This calculation shows that the density of standard air, based on the provided specific volume, aligns with a value of 0.075 pounds per cubic foot. This value appropriately represents the density of air under standard conditions, making it consistent with what is commonly accepted in HVAC calculations. Understanding this relationship is crucial for HVAC practitioners as it helps to determine

To find the density of standard air when given the specific volume, we can use the relationship between density and specific volume. The specific volume is defined as the volume occupied by a unit mass of a substance, and it is the inverse of density. In mathematical terms, density is equal to the mass divided by volume, and the specific volume is volume divided by mass.

Given the specific volume of 13.33 cubic feet per pound, we can calculate the density (in pounds per cubic foot) using the following formula:

[

\text{Density} = \frac{1}{\text{Specific Volume}}

]

Substituting the specific volume into the equation gives:

[

\text{Density} = \frac{1}{13.33 , \text{cubic feet per pound}} \approx 0.075 , \text{pounds per cubic foot}

]

This calculation shows that the density of standard air, based on the provided specific volume, aligns with a value of 0.075 pounds per cubic foot. This value appropriately represents the density of air under standard conditions, making it consistent with what is commonly accepted in HVAC calculations. Understanding this relationship is crucial for HVAC practitioners as it helps to determine