If a motor compressor has a 2" bore and a 3" stroke, what is the calculated piston displacement in cubic inches?

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Multiple Choice

If a motor compressor has a 2" bore and a 3" stroke, what is the calculated piston displacement in cubic inches?

Explanation:
To find the piston displacement of a motor compressor, you can use the formula for the volume of a cylinder: \[ \text{Volume} = \pi \times \left( \frac{D}{2} \right)^2 \times H \] where \(D\) is the bore diameter, \(H\) is the stroke length, and \(\pi\) is approximately 3.14. In this case, the bore diameter is 2 inches, and the stroke is 3 inches. First, calculate the radius, which is half the diameter: \[ \text{Radius} = \frac{D}{2} = \frac{2}{2} = 1 \text{ inch} \] Now substitute the values into the volume formula: \[ \text{Volume} = \pi \times (1)^2 \times 3 \] This simplifies to: \[ \text{Volume} = \pi \times 1 \times 3 = 3\pi \] Now, substituting \(\pi\) with approximately 3.14: \[ 3\pi \approx 3 \times 3.14 = 9

To find the piston displacement of a motor compressor, you can use the formula for the volume of a cylinder:

[

\text{Volume} = \pi \times \left( \frac{D}{2} \right)^2 \times H

]

where (D) is the bore diameter, (H) is the stroke length, and (\pi) is approximately 3.14.

In this case, the bore diameter is 2 inches, and the stroke is 3 inches. First, calculate the radius, which is half the diameter:

[

\text{Radius} = \frac{D}{2} = \frac{2}{2} = 1 \text{ inch}

]

Now substitute the values into the volume formula:

[

\text{Volume} = \pi \times (1)^2 \times 3

]

This simplifies to:

[

\text{Volume} = \pi \times 1 \times 3 = 3\pi

]

Now, substituting (\pi) with approximately 3.14:

[

3\pi \approx 3 \times 3.14 = 9

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